Optimal. Leaf size=331 \[ \frac {\sqrt {d+e x} (a e+c d x)}{a \sqrt {a+c x^2} \left (a e^2+c d^2\right )}-\frac {\sqrt {c} d \sqrt {\frac {c x^2}{a}+1} \sqrt {d+e x} E\left (\sin ^{-1}\left (\frac {\sqrt {1-\frac {\sqrt {c} x}{\sqrt {-a}}}}{\sqrt {2}}\right )|-\frac {2 a e}{\sqrt {-a} \sqrt {c} d-a e}\right )}{\sqrt {-a} \sqrt {a+c x^2} \left (a e^2+c d^2\right ) \sqrt {\frac {\sqrt {c} (d+e x)}{\sqrt {-a} e+\sqrt {c} d}}}+\frac {\sqrt {\frac {c x^2}{a}+1} \sqrt {\frac {\sqrt {c} (d+e x)}{\sqrt {-a} e+\sqrt {c} d}} F\left (\sin ^{-1}\left (\frac {\sqrt {1-\frac {\sqrt {c} x}{\sqrt {-a}}}}{\sqrt {2}}\right )|-\frac {2 a e}{\sqrt {-a} \sqrt {c} d-a e}\right )}{\sqrt {-a} \sqrt {c} \sqrt {a+c x^2} \sqrt {d+e x}} \]
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Rubi [A] time = 0.22, antiderivative size = 331, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.238, Rules used = {741, 844, 719, 424, 419} \[ \frac {\sqrt {d+e x} (a e+c d x)}{a \sqrt {a+c x^2} \left (a e^2+c d^2\right )}-\frac {\sqrt {c} d \sqrt {\frac {c x^2}{a}+1} \sqrt {d+e x} E\left (\sin ^{-1}\left (\frac {\sqrt {1-\frac {\sqrt {c} x}{\sqrt {-a}}}}{\sqrt {2}}\right )|-\frac {2 a e}{\sqrt {-a} \sqrt {c} d-a e}\right )}{\sqrt {-a} \sqrt {a+c x^2} \left (a e^2+c d^2\right ) \sqrt {\frac {\sqrt {c} (d+e x)}{\sqrt {-a} e+\sqrt {c} d}}}+\frac {\sqrt {\frac {c x^2}{a}+1} \sqrt {\frac {\sqrt {c} (d+e x)}{\sqrt {-a} e+\sqrt {c} d}} F\left (\sin ^{-1}\left (\frac {\sqrt {1-\frac {\sqrt {c} x}{\sqrt {-a}}}}{\sqrt {2}}\right )|-\frac {2 a e}{\sqrt {-a} \sqrt {c} d-a e}\right )}{\sqrt {-a} \sqrt {c} \sqrt {a+c x^2} \sqrt {d+e x}} \]
Antiderivative was successfully verified.
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Rule 419
Rule 424
Rule 719
Rule 741
Rule 844
Rubi steps
\begin {align*} \int \frac {1}{\sqrt {d+e x} \left (a+c x^2\right )^{3/2}} \, dx &=\frac {(a e+c d x) \sqrt {d+e x}}{a \left (c d^2+a e^2\right ) \sqrt {a+c x^2}}-\frac {\int \frac {-\frac {a e^2}{2}+\frac {1}{2} c d e x}{\sqrt {d+e x} \sqrt {a+c x^2}} \, dx}{a \left (c d^2+a e^2\right )}\\ &=\frac {(a e+c d x) \sqrt {d+e x}}{a \left (c d^2+a e^2\right ) \sqrt {a+c x^2}}+\frac {\int \frac {1}{\sqrt {d+e x} \sqrt {a+c x^2}} \, dx}{2 a}-\frac {(c d) \int \frac {\sqrt {d+e x}}{\sqrt {a+c x^2}} \, dx}{2 a \left (c d^2+a e^2\right )}\\ &=\frac {(a e+c d x) \sqrt {d+e x}}{a \left (c d^2+a e^2\right ) \sqrt {a+c x^2}}-\frac {\left (\sqrt {c} d \sqrt {d+e x} \sqrt {1+\frac {c x^2}{a}}\right ) \operatorname {Subst}\left (\int \frac {\sqrt {1+\frac {2 a \sqrt {c} e x^2}{\sqrt {-a} \left (c d-\frac {a \sqrt {c} e}{\sqrt {-a}}\right )}}}{\sqrt {1-x^2}} \, dx,x,\frac {\sqrt {1-\frac {\sqrt {c} x}{\sqrt {-a}}}}{\sqrt {2}}\right )}{\sqrt {-a} \left (c d^2+a e^2\right ) \sqrt {\frac {c (d+e x)}{c d-\frac {a \sqrt {c} e}{\sqrt {-a}}}} \sqrt {a+c x^2}}+\frac {\left (\sqrt {\frac {c (d+e x)}{c d-\frac {a \sqrt {c} e}{\sqrt {-a}}}} \sqrt {1+\frac {c x^2}{a}}\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {1-x^2} \sqrt {1+\frac {2 a \sqrt {c} e x^2}{\sqrt {-a} \left (c d-\frac {a \sqrt {c} e}{\sqrt {-a}}\right )}}} \, dx,x,\frac {\sqrt {1-\frac {\sqrt {c} x}{\sqrt {-a}}}}{\sqrt {2}}\right )}{\sqrt {-a} \sqrt {c} \sqrt {d+e x} \sqrt {a+c x^2}}\\ &=\frac {(a e+c d x) \sqrt {d+e x}}{a \left (c d^2+a e^2\right ) \sqrt {a+c x^2}}-\frac {\sqrt {c} d \sqrt {d+e x} \sqrt {1+\frac {c x^2}{a}} E\left (\sin ^{-1}\left (\frac {\sqrt {1-\frac {\sqrt {c} x}{\sqrt {-a}}}}{\sqrt {2}}\right )|-\frac {2 a e}{\sqrt {-a} \sqrt {c} d-a e}\right )}{\sqrt {-a} \left (c d^2+a e^2\right ) \sqrt {\frac {\sqrt {c} (d+e x)}{\sqrt {c} d+\sqrt {-a} e}} \sqrt {a+c x^2}}+\frac {\sqrt {\frac {\sqrt {c} (d+e x)}{\sqrt {c} d+\sqrt {-a} e}} \sqrt {1+\frac {c x^2}{a}} F\left (\sin ^{-1}\left (\frac {\sqrt {1-\frac {\sqrt {c} x}{\sqrt {-a}}}}{\sqrt {2}}\right )|-\frac {2 a e}{\sqrt {-a} \sqrt {c} d-a e}\right )}{\sqrt {-a} \sqrt {c} \sqrt {d+e x} \sqrt {a+c x^2}}\\ \end {align*}
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Mathematica [C] time = 0.96, size = 430, normalized size = 1.30 \[ \frac {e x \left (\sqrt {c} d-i \sqrt {a} e\right ) \sqrt {-d-\frac {i \sqrt {a} e}{\sqrt {c}}}+\sqrt {a} e (d+e x)^{3/2} \sqrt {\frac {e \left (x+\frac {i \sqrt {a}}{\sqrt {c}}\right )}{d+e x}} \sqrt {-\frac {-e x+\frac {i \sqrt {a} e}{\sqrt {c}}}{d+e x}} F\left (i \sinh ^{-1}\left (\frac {\sqrt {-d-\frac {i \sqrt {a} e}{\sqrt {c}}}}{\sqrt {d+e x}}\right )|\frac {\sqrt {c} d-i \sqrt {a} e}{\sqrt {c} d+i \sqrt {a} e}\right )+i \sqrt {c} d (d+e x)^{3/2} \sqrt {\frac {e \left (x+\frac {i \sqrt {a}}{\sqrt {c}}\right )}{d+e x}} \sqrt {-\frac {-e x+\frac {i \sqrt {a} e}{\sqrt {c}}}{d+e x}} E\left (i \sinh ^{-1}\left (\frac {\sqrt {-d-\frac {i \sqrt {a} e}{\sqrt {c}}}}{\sqrt {d+e x}}\right )|\frac {\sqrt {c} d-i \sqrt {a} e}{\sqrt {c} d+i \sqrt {a} e}\right )}{a e \sqrt {a+c x^2} \sqrt {d+e x} \left (\sqrt {c} d-i \sqrt {a} e\right ) \sqrt {-d-\frac {i \sqrt {a} e}{\sqrt {c}}}} \]
Antiderivative was successfully verified.
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fricas [F] time = 1.01, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {\sqrt {c x^{2} + a} \sqrt {e x + d}}{c^{2} e x^{5} + c^{2} d x^{4} + 2 \, a c e x^{3} + 2 \, a c d x^{2} + a^{2} e x + a^{2} d}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{{\left (c x^{2} + a\right )}^{\frac {3}{2}} \sqrt {e x + d}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.13, size = 696, normalized size = 2.10 \[ \frac {\left (c^{2} d \,e^{2} x^{2}+\sqrt {-\frac {\left (e x +d \right ) c}{-c d +\sqrt {-a c}\, e}}\, \sqrt {\frac {\left (-c x +\sqrt {-a c}\right ) e}{c d +\sqrt {-a c}\, e}}\, \sqrt {\frac {\left (c x +\sqrt {-a c}\right ) e}{-c d +\sqrt {-a c}\, e}}\, a c d \,e^{2} \EllipticE \left (\sqrt {-\frac {\left (e x +d \right ) c}{-c d +\sqrt {-a c}\, e}}, \sqrt {-\frac {-c d +\sqrt {-a c}\, e}{c d +\sqrt {-a c}\, e}}\right )+a c \,e^{3} x +\sqrt {-\frac {\left (e x +d \right ) c}{-c d +\sqrt {-a c}\, e}}\, \sqrt {\frac {\left (-c x +\sqrt {-a c}\right ) e}{c d +\sqrt {-a c}\, e}}\, \sqrt {\frac {\left (c x +\sqrt {-a c}\right ) e}{-c d +\sqrt {-a c}\, e}}\, c^{2} d^{3} \EllipticE \left (\sqrt {-\frac {\left (e x +d \right ) c}{-c d +\sqrt {-a c}\, e}}, \sqrt {-\frac {-c d +\sqrt {-a c}\, e}{c d +\sqrt {-a c}\, e}}\right )+c^{2} d^{2} e x +a c d \,e^{2}-\sqrt {-a c}\, \sqrt {-\frac {\left (e x +d \right ) c}{-c d +\sqrt {-a c}\, e}}\, \sqrt {\frac {\left (-c x +\sqrt {-a c}\right ) e}{c d +\sqrt {-a c}\, e}}\, \sqrt {\frac {\left (c x +\sqrt {-a c}\right ) e}{-c d +\sqrt {-a c}\, e}}\, a \,e^{3} \EllipticF \left (\sqrt {-\frac {\left (e x +d \right ) c}{-c d +\sqrt {-a c}\, e}}, \sqrt {-\frac {-c d +\sqrt {-a c}\, e}{c d +\sqrt {-a c}\, e}}\right )-\sqrt {-a c}\, \sqrt {-\frac {\left (e x +d \right ) c}{-c d +\sqrt {-a c}\, e}}\, \sqrt {\frac {\left (-c x +\sqrt {-a c}\right ) e}{c d +\sqrt {-a c}\, e}}\, \sqrt {\frac {\left (c x +\sqrt {-a c}\right ) e}{-c d +\sqrt {-a c}\, e}}\, c \,d^{2} e \EllipticF \left (\sqrt {-\frac {\left (e x +d \right ) c}{-c d +\sqrt {-a c}\, e}}, \sqrt {-\frac {-c d +\sqrt {-a c}\, e}{c d +\sqrt {-a c}\, e}}\right )\right ) \sqrt {e x +d}\, \sqrt {c \,x^{2}+a}}{\left (a \,e^{2}+c \,d^{2}\right ) \left (c e \,x^{3}+c d \,x^{2}+a e x +a d \right ) a c e} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{{\left (c x^{2} + a\right )}^{\frac {3}{2}} \sqrt {e x + d}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {1}{{\left (c\,x^2+a\right )}^{3/2}\,\sqrt {d+e\,x}} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{\left (a + c x^{2}\right )^{\frac {3}{2}} \sqrt {d + e x}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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